Writing clean and comprehensible code is pivotal for collaborative development. Here are four strategies to elegantly eliminate if-else
blocks from your Java codebase.
1. Option 1: Early Return
In scenarios requiring simple conditional checks, employ early returns to streamline the code flow:
public boolean isValid(String condition) {
if (condition == null) {
return false;
}
return condition.equals("hi");
}
2. Option 2: Enumeration
Leverage enums for mapping fixed values to more descriptive labels, enhancing code readability:
public enum StatusLabelEnum {
Padding(1, "Padding"),
Paid(2, "Paid"),
Success(3, "Success"),
Failed(4, "Failed");
// Constructor, fields, and methods...
public static String getLabelByStatus(int status) {
// Logic to fetch label by status...
}
}
public String getLabel(int status) {
return StatusLabelEnum.getLabelByStatus(status);
}
3. Option 3: Optional
Utilize Java Optional
to elegantly handle potential null values:
public int getOrderStatus(UUID id) {
Order order = getOrderById(id);
return Optional.ofNullable(order)
.map(Order::getOrderStatus)
.orElse(1);
}
4. Option 4: Table-Driven Method
Implement a table-driven approach for cleaner branching logic, reducing nested if-else
blocks:
// Interface for action services
public interface ActionService {
void doAction();
}
// Sample implementation
public class ActionService1 implements ActionService {
public void doAction() {
// Implementation for action 1
}
}
// Usage of the table-driven method
Map<String, ActionService> actionMap = new HashMap<>();
actionMap.put("code1", new ActionService1());
// Add other codes and corresponding services...
// Invoke action based on code
actionMap.get(action).doAction();
Embrace these techniques judiciously to enhance code readability and maintainability. Each approach caters to specific scenarios, ensuring your code remains elegant and easily understandable.
Happy coding!